Question Number 149468 by mathdanisur last updated on 05/Aug/21

sin𝛂 ∙ cos𝛂 = (3/8) ⇒ 3∣sin𝛂 - cos𝛂∣=?

Answered by Olaf_Thorendsen last updated on 05/Aug/21

Let x = 3∣sinα−cosα∣ x^2 = 9(sin^2 +cos^2 α−2sinα.cosα) x^2 = 9(1−2×(3/8)) = (9/4) x = (3/2)

Commented bymathdanisur last updated on 05/Aug/21

Thankyou Ser, but ans: 1,5

Commented byOlaf_Thorendsen last updated on 05/Aug/21

Sorry, I corrected.

Commented bymathdanisur last updated on 06/Aug/21

Thanks Ser