Question Number 149503 by mathdanisur last updated on 05/Aug/21

Calcular: 3sin∙(150 - 𝛂) - 2cos∙(60 - 𝛂) = (1/2)

Answered by MJS_new last updated on 05/Aug/21

⇔ 3sin (α+30) −2sin (α+30) =(1/2) ⇔ sin (α+30) =(1/2) ⇔ α=360n∨α=120+360n ∀n∈Z

Commented bymathdanisur last updated on 05/Aug/21

Cool, thank you Ser

Answered by Ar Brandon last updated on 05/Aug/21

3sin(150°−α)−2cos(60°−α)=(1/2) 3sin(90°+60°−α)−2cos(60°−α)=(1/2) 3cos(60°−α)−2cos(60°−α)=(1/2) cos(60°−α)=(1/2)⇒60°−α=±60°+360n° ⇒α=60°∓60°−360n°, n∈Z

Commented bymathdanisur last updated on 06/Aug/21

Thankyou Ser