Question Number 14963 by tawa tawa last updated on 06/Jun/17

A resistor R is connected in series with a parallel combination of two resistors of 24 and 8 ohms . The total power disipated in the circuit is 64 watt when the applied voltage is 24 volt.Find R

Answered by ajfour last updated on 06/Jun/17

P=(V^2 /R_(eq) ) , R_(eq) =R+((24×8)/(32))Ω =R+6Ω ; ⇒ 64W=(((24V)^2 )/((R+6Ω))) or, R+6Ω=((24×24)/(64)) Ω R = 9Ω−6Ω =3Ω .

Commented bytawa tawa last updated on 06/Jun/17

God bless you sir.