Question Number 159078 by LEKOUMA last updated on 12/Nov/21
$$\left.\mathrm{1}\right)\:{Prove}\:{by}\:{recurrence}\:{that}\: \\ $$$${for}\:{n}\geqslant\mathrm{28},\:\:\:{n}!\geqslant\mathrm{11}^{{n}} \: \\ $$$$\left.\mathrm{2}\right)\:{On}\:{subtract}\:{the}\:{limit}\:{of}\:{the}\: \\ $$$${suite}\:\left(\frac{{n}!}{\mathrm{10}^{{n}} }\right)\:{when}\:{n}\:{tended}\:{at}\:+\infty \\ $$