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Question Number 159453 by Avijit007 last updated on 17/Nov/21

x and y are real value and   x+iy=(5/(−3+4i)) find x and y.(i=(√(−1)))

$$\mathrm{x}\:{and}\:\mathrm{y}\:{are}\:{real}\:{value}\:{and} \\ $$$$\:\mathrm{x}+\mathrm{iy}=\frac{\mathrm{5}}{−\mathrm{3}+\mathrm{4}{i}}\:{find}\:\mathrm{x}\:{and}\:\mathrm{y}.\left(\mathrm{i}=\sqrt{−\mathrm{1}}\right) \\ $$

Commented by Avijit007 last updated on 17/Nov/21

help.

$${help}. \\ $$

Answered by Ar Brandon last updated on 17/Nov/21

x+iy=(5/(−3+4i))×((−3−4i)/(−3−4i))             =((−15−20i)/(9+16))=−((3/5)+(4/5)i)             x=−(3/5) , y=−(4/5)

$${x}+{iy}=\frac{\mathrm{5}}{−\mathrm{3}+\mathrm{4}{i}}×\frac{−\mathrm{3}−\mathrm{4}{i}}{−\mathrm{3}−\mathrm{4}{i}} \\ $$$$\:\:\:\:\:\:\:\:\:\:\:=\frac{−\mathrm{15}−\mathrm{20}{i}}{\mathrm{9}+\mathrm{16}}=−\left(\frac{\mathrm{3}}{\mathrm{5}}+\frac{\mathrm{4}}{\mathrm{5}}{i}\right) \\ $$$$\:\:\:\:\:\:\:\:\:\:\:{x}=−\frac{\mathrm{3}}{\mathrm{5}}\:,\:{y}=−\frac{\mathrm{4}}{\mathrm{5}} \\ $$

Commented by Avijit007 last updated on 17/Nov/21

thank you : )

$$\left.{thank}\:{you}\::\:\right) \\ $$

Commented by Ar Brandon last updated on 17/Nov/21

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