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Question Number 166929 by MathsFan last updated on 02/Mar/22

 A particle of mass 0.25kg vibrates   with a period of 2secs. If its    greatest displacement is 0.4m. What   is its maximum kinetic energy.

$$\:{A}\:{particle}\:{of}\:{mass}\:\mathrm{0}.\mathrm{25}{kg}\:{vibrates} \\ $$$$\:{with}\:{a}\:{period}\:{of}\:\mathrm{2}{secs}.\:{If}\:{its}\: \\ $$$$\:{greatest}\:{displacement}\:{is}\:\mathrm{0}.\mathrm{4}{m}.\:{What} \\ $$$$\:{is}\:{its}\:{maximum}\:{kinetic}\:{energy}. \\ $$

Answered by mr W last updated on 02/Mar/22

ω=((2π)/T)  KE_(max) =((mv_(max) ^2 )/2)  =((m(ωs_(max) )^2 )/2)  =(m/2)(((2πs_(max) )/T))^2   =((0.25)/2)×(((2π×0.4)/2))^2 =0.1974 J

$$\omega=\frac{\mathrm{2}\pi}{{T}} \\ $$$${KE}_{{max}} =\frac{{mv}_{{max}} ^{\mathrm{2}} }{\mathrm{2}} \\ $$$$=\frac{{m}\left(\omega{s}_{{max}} \right)^{\mathrm{2}} }{\mathrm{2}} \\ $$$$=\frac{{m}}{\mathrm{2}}\left(\frac{\mathrm{2}\pi{s}_{{max}} }{{T}}\right)^{\mathrm{2}} \\ $$$$=\frac{\mathrm{0}.\mathrm{25}}{\mathrm{2}}×\left(\frac{\mathrm{2}\pi×\mathrm{0}.\mathrm{4}}{\mathrm{2}}\right)^{\mathrm{2}} =\mathrm{0}.\mathrm{1974}\:{J} \\ $$

Commented by MathsFan last updated on 02/Mar/22

thank you champion

$${thank}\:{you}\:{champion} \\ $$

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