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Question Number 167418 by Bagus1003 last updated on 16/Mar/22

x^y =z  (z)^(1/y) =x  log_x (z)=y

$${x}^{{y}} ={z} \\ $$$$\sqrt[{{y}}]{{z}}={x} \\ $$$$\mathrm{log}_{{x}} \left({z}\right)={y} \\ $$

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