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Question Number 168593 by Giantyusuf last updated on 13/Apr/22

Commented by mr W last updated on 13/Apr/22

question is wrong. see168477.

$${question}\:{is}\:{wrong}.\:{see}\mathrm{168477}. \\ $$

Commented by MJS_new last updated on 13/Apr/22

besides this I don′t think we can solve  ∫((sin x)/(cos^(−1)  x))dx  at least I found no solution

$$\mathrm{besides}\:\mathrm{this}\:\mathrm{I}\:\mathrm{don}'\mathrm{t}\:\mathrm{think}\:\mathrm{we}\:\mathrm{can}\:\mathrm{solve} \\ $$$$\int\frac{\mathrm{sin}\:{x}}{\mathrm{cos}^{−\mathrm{1}} \:{x}}{dx} \\ $$$$\mathrm{at}\:\mathrm{least}\:\mathrm{I}\:\mathrm{found}\:\mathrm{no}\:\mathrm{solution} \\ $$

Commented by cortano1 last updated on 14/Apr/22

 f(x)= ((sin x)/(arccos x))    ∫_0 ^( (π/3)) ((sin x)/(arccos x)) dx ⇒doesn′t make sense

$$\:{f}\left({x}\right)=\:\frac{\mathrm{sin}\:{x}}{\mathrm{arccos}\:{x}}\: \\ $$$$\:\int_{\mathrm{0}} ^{\:\frac{\pi}{\mathrm{3}}} \frac{\mathrm{sin}\:{x}}{\mathrm{arccos}\:{x}}\:{dx}\:\Rightarrow{doesn}'{t}\:{make}\:{sense} \\ $$

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