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Question Number 174888 by ajfour last updated on 13/Aug/22

Answered by aleks041103 last updated on 13/Aug/22

if O is center of circle:  ∠AOB=∠QOP⇒AB^(⌢) =PQ^(⌢)   ⇒AB=PQ  By analogy:  a=p  b=q  c=r

$${if}\:{O}\:{is}\:{center}\:{of}\:{circle}: \\ $$$$\angle{AOB}=\angle{QOP}\Rightarrow\overset{\frown} {{AB}}=\overset{\frown} {{PQ}} \\ $$$$\Rightarrow{AB}={PQ} \\ $$$${By}\:{analogy}: \\ $$$${a}={p} \\ $$$${b}={q} \\ $$$${c}={r} \\ $$

Commented by ajfour last updated on 14/Aug/22

your eyes seem wide-open to me  all the time, sir (^(   ) ((★_(           _(  ) ⌊_ ⌋) ^⌢ ★^⌢ ))

$${your}\:{eyes}\:{seem}\:{wide}-{open}\:{to}\:{me} \\ $$$${all}\:{the}\:{time},\:{sir}\:\overset{\:\:\:} {\left(}\left(\left(\underset{\:\:\:\:\:\:\:\:\:\:\underset{\:\:} {\:}\underset{} {\lfloor}\rfloor} {\overset{\frown} {\bigstar}}\overset{\frown} {\bigstar}\right)\right)\right. \\ $$

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