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Question Number 175008 by BagusSetyoWibowo last updated on 16/Aug/22

Find The Centroid Coordinate   If Trapezoid With B_1 =4, B_2 =3  And Height=5 With Positions   Like This

$${Find}\:{The}\:{Centroid}\:{Coordinate}\: \\ $$$${If}\:{Trapezoid}\:{With}\:{B}_{\mathrm{1}} =\mathrm{4},\:{B}_{\mathrm{2}} =\mathrm{3} \\ $$$${And}\:{Height}=\mathrm{5}\:{With}\:{Positions}\: \\ $$$${Like}\:{This} \\ $$

Commented by BagusSetyoWibowo last updated on 16/Aug/22

Commented by Frix last updated on 16/Aug/22

line AC: y=(4/5)x  line BD: y=−(3/5)x+4  ⇒  (4/5)x=−(3/5)x+4  x=((20)/7)∧y=((16)/7)  E= (((20/7)),((16/7)) )

$$\mathrm{line}\:{A}\mathrm{C}:\:{y}=\frac{\mathrm{4}}{\mathrm{5}}{x} \\ $$$$\mathrm{line}\:{BD}:\:{y}=−\frac{\mathrm{3}}{\mathrm{5}}{x}+\mathrm{4} \\ $$$$\Rightarrow \\ $$$$\frac{\mathrm{4}}{\mathrm{5}}{x}=−\frac{\mathrm{3}}{\mathrm{5}}{x}+\mathrm{4} \\ $$$${x}=\frac{\mathrm{20}}{\mathrm{7}}\wedge{y}=\frac{\mathrm{16}}{\mathrm{7}} \\ $$$${E}=\begin{pmatrix}{\mathrm{20}/\mathrm{7}}\\{\mathrm{16}/\mathrm{7}}\end{pmatrix} \\ $$

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