Question and Answers Forum

All Questions      Topic List

Chemical Bonding Questions

Previous in All Question      Next in All Question      

Previous in Chemical Bonding      Next in Chemical Bonding      

Question Number 177725 by Spillover last updated on 08/Oct/22

Find the oxidation number of the underlined element in the following (a)KCl O_3 (b)SO_3 ^(2−) (c)H_2 SO_4 (d)Na H

$$\mathrm{Find}\:\mathrm{the}\:\mathrm{oxidation}\:\mathrm{number}\:\mathrm{of}\:\mathrm{the} \\ $$$$\mathrm{underlined}\:\mathrm{element}\:\mathrm{in}\:\mathrm{the} \\ $$$$\:\mathrm{following} \\ $$$$\left(\mathrm{a}\right)\mathrm{K}\underline{\boldsymbol{\mathrm{Cl}}}\:\mathrm{O}_{\mathrm{3}} \\ $$$$\left(\mathrm{b}\right)\underline{\mathrm{S}O}_{\mathrm{3}} ^{\mathrm{2}−} \\ $$$$\left(\mathrm{c}\right)\mathrm{H}_{\mathrm{2}} \underline{\mathrm{S}O}_{\mathrm{4}} \\ $$$$\left(\mathrm{d}\right)\underline{\mathrm{Na}}\:\mathrm{H} \\ $$$$ \\ $$

Commented by Tawa11 last updated on 08/Oct/22

(a) 1 + x − 6 = 0 x − 5 = 0 x = 5 [Cl = 5] (b) x − 6 = − 2 x = − 2 + 6 x = 4 [S = 4] (c) 2 + x − 8 = 0 x − 6 = 0 x = 6 [S = 6] (d) x − 1 = 0 x = 1 [Na = 1]

$$\left(\mathrm{a}\right)\:\:\:\:\:\mathrm{1}\:\:+\:\:\mathrm{x}\:\:−\:\:\mathrm{6}\:\:\:=\:\:\:\mathrm{0} \\ $$$$\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\mathrm{x}\:\:\:−\:\:\:\mathrm{5}\:\:\:=\:\:\:\mathrm{0} \\ $$$$\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\mathrm{x}\:\:\:=\:\:\:\mathrm{5}\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\left[\mathrm{Cl}\:\:\:=\:\:\:\mathrm{5}\right] \\ $$$$ \\ $$$$\left(\mathrm{b}\right)\:\:\:\:\:\mathrm{x}\:\:\:−\:\:\:\mathrm{6}\:\:\:\:=\:\:\:\:−\:\:\mathrm{2} \\ $$$$\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\mathrm{x}\:\:\:\:=\:\:\:−\:\:\mathrm{2}\:\:\:+\:\:\:\mathrm{6} \\ $$$$\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\mathrm{x}\:\:\:=\:\:\:\mathrm{4}\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\left[\mathrm{S}\:\:\:=\:\:\:\mathrm{4}\right] \\ $$$$ \\ $$$$\left(\mathrm{c}\right)\:\:\:\:\:\mathrm{2}\:\:\:+\:\:\:\mathrm{x}\:\:\:−\:\:\:\mathrm{8}\:\:\:\:=\:\:\:\mathrm{0} \\ $$$$\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\mathrm{x}\:\:\:−\:\:\:\mathrm{6}\:\:\:=\:\:\:\mathrm{0} \\ $$$$\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\mathrm{x}\:\:\:=\:\:\:\mathrm{6}\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\left[\mathrm{S}\:\:\:=\:\:\:\mathrm{6}\right] \\ $$$$ \\ $$$$\left(\mathrm{d}\right)\:\:\:\:\:\:\:\mathrm{x}\:\:\:−\:\:\:\mathrm{1}\:\:\:=\:\:\:\mathrm{0} \\ $$$$\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\mathrm{x}\:\:\:=\:\:\:\mathrm{1}\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\left[\mathrm{Na}\:\:\:=\:\:\:\mathrm{1}\right] \\ $$

Commented by Spillover last updated on 08/Oct/22

perfect.

$$\mathrm{perfect}. \\ $$

Terms of Service

Privacy Policy

Contact: info@tinkutara.com