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Question Number 180365 by Acem last updated on 11/Nov/22

Answered by greougoury555 last updated on 11/Nov/22

let ∠ ABC = β ∠ AOC= 360°−2β 2α +360°−2β = 180 ⇔ β−α = ((360°−180°)/2) =90°

$${let}\:\angle\:{ABC}\:=\:\beta \\ $$$$\angle\:{AOC}=\:\mathrm{360}°−\mathrm{2}\beta \\ $$$$\:\mathrm{2}\alpha\:+\mathrm{360}°−\mathrm{2}\beta\:=\:\mathrm{180} \\ $$$$\:\Leftrightarrow\:\beta−\alpha\:=\:\frac{\mathrm{360}°−\mathrm{180}°}{\mathrm{2}}\:=\mathrm{90}° \\ $$

Commented by Acem last updated on 11/Nov/22

Thanks!

$${Thanks}! \\ $$

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