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Question Number 181151 by mr W last updated on 22/Nov/22

Answered by SEKRET last updated on 22/Nov/22

(√2)

$$\:\sqrt{\mathrm{2}} \\ $$

Answered by SEKRET last updated on 22/Nov/22

$$ \\ $$

Commented by Rasheed.Sindhi last updated on 22/Nov/22

Advanced booking for answer?

$${Advanced}\:{booking}\:{for}\:{answer}? \\ $$

Commented by Acem last updated on 22/Nov/22

@Rasheed, You made me laugh

$$\:@{Rasheed},\:{You}\:{made}\:{me}\:{laugh} \\ $$

Commented by Rasheed.Sindhi last updated on 23/Nov/22

Good morning Acem sir!

Answered by Acem last updated on 22/Nov/22

Commented by mr W last updated on 22/Nov/22

��

Commented by Acem last updated on 22/Nov/22

; m= ℓ cos β

$$\:;\:{m}=\:\ell\:\mathrm{cos}\:\beta \\ $$

Answered by mr W last updated on 22/Nov/22

Commented by Acem last updated on 22/Nov/22

I liked this question!

$${I}\:{liked}\:{this}\:{question}! \\ $$

Commented by mr W last updated on 22/Nov/22

3^2 +(3+y)^2 =5^2 ⇒y=1 x^2 =1^2 +(5−1−3)^2 =2 ⇒x=(√2)

$$\mathrm{3}^{\mathrm{2}} +\left(\mathrm{3}+{y}\right)^{\mathrm{2}} =\mathrm{5}^{\mathrm{2}} \\ $$$$\Rightarrow{y}=\mathrm{1} \\ $$$${x}^{\mathrm{2}} =\mathrm{1}^{\mathrm{2}} +\left(\mathrm{5}−\mathrm{1}−\mathrm{3}\right)^{\mathrm{2}} =\mathrm{2} \\ $$$$\Rightarrow{x}=\sqrt{\mathrm{2}} \\ $$

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