Question Number 181628 by Tawa11 last updated on 27/Nov/22
$$\mathrm{find}\:\mathrm{the}\:\mathrm{domain}\:\mathrm{and}\:\mathrm{range}\:\mathrm{of}\:\:\:\mathrm{y}\:\:=\:\:\frac{\mathrm{1}}{\left(\mathrm{x}\:\:−\:\:\mathrm{1}\right)\left(\mathrm{x}\:\:+\:\:\mathrm{2}\right)} \\ $$$$\mathrm{restricted}\:\mathrm{to}\:\:\:\mathrm{0}\:\:\leqslant\:\:\mathrm{x}\:\:\leqslant\:\:\mathrm{6} \\ $$
Answered by Acem last updated on 27/Nov/22
Commented by Acem last updated on 27/Nov/22
$$\circledast\:\frac{\mathrm{1}}{\mathrm{0}^{\:\pm} } \\ $$
Commented by mr W last updated on 28/Nov/22
![domain: [0,6]−{1} range: (−∞,−(1/2)] ∩[(1/(40)),+∞)](Q181647.png)
$${domain}: \\ $$$$\left[\mathrm{0},\mathrm{6}\right]−\left\{\mathrm{1}\right\} \\ $$$${range}: \\ $$$$\left(−\infty,−\frac{\mathrm{1}}{\mathrm{2}}\right]\:\cap\left[\frac{\mathrm{1}}{\mathrm{40}},+\infty\right) \\ $$
Commented by Tawa11 last updated on 28/Nov/22
$$\mathrm{God}\:\mathrm{bless}\:\mathrm{you}\:\mathrm{sirs}. \\ $$