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Question Number 183135 by Tawa11 last updated on 21/Dec/22

Answered by TheSupreme last updated on 21/Dec/22

((Δy)/(Δh))=((y(x+h)−y(x))/h)=((2(x+h)^2 −2x^2 +5h)/h)=  =((2h(2x+h)+5h)/h)=4x+5+2h  x=2  ((Δy)/(Δh))=13+2h   if h=0  ((Δy)/(Δx))=13

$$\frac{\Delta{y}}{\Delta{h}}=\frac{{y}\left({x}+{h}\right)−{y}\left({x}\right)}{{h}}=\frac{\mathrm{2}\left({x}+{h}\right)^{\mathrm{2}} −\mathrm{2}{x}^{\mathrm{2}} +\mathrm{5}{h}}{{h}}= \\ $$$$=\frac{\mathrm{2}{h}\left(\mathrm{2}{x}+{h}\right)+\mathrm{5}{h}}{{h}}=\mathrm{4}{x}+\mathrm{5}+\mathrm{2}{h} \\ $$$${x}=\mathrm{2} \\ $$$$\frac{\Delta{y}}{\Delta{h}}=\mathrm{13}+\mathrm{2}{h}\: \\ $$$${if}\:{h}=\mathrm{0} \\ $$$$\frac{\Delta{y}}{\Delta{x}}=\mathrm{13} \\ $$

Commented by Tawa11 last updated on 21/Dec/22

God bless you sir. I appreciate.

$$\mathrm{God}\:\mathrm{bless}\:\mathrm{you}\:\mathrm{sir}.\:\mathrm{I}\:\mathrm{appreciate}. \\ $$

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