Question Number 190639 by otchereabdullai last updated on 07/Apr/23
$$\:{The}\:{points}\:{A},\:{B}\:{and}\:{C}\:{have}\:{position} \\ $$$$\:{vectors}\:{i}−{j}\:,\:\mathrm{5}{i}−\mathrm{3}{j}\:{and}\:\mathrm{11}{i}−\mathrm{6}{j}\: \\ $$$${respectively}\:.\:{Show}\:{that}\:{A},\:{B}\:{and}\:{C} \\ $$$${are}\:{collinear}. \\ $$
Answered by ajfour last updated on 08/Apr/23
$${BC}=\mathrm{6}{i}−\mathrm{3}{j}=\mathrm{3}\left(\mathrm{2}{i}−{j}\right) \\ $$$${AB}=\mathrm{4}{i}−\mathrm{2}{j}=\mathrm{2}\left(\mathrm{2}{i}−{j}\right) \\ $$
Commented by otchereabdullai last updated on 08/Apr/23
$${thanks}\:{a}\:{lot}\:{prof}\:{Aj} \\ $$