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Question Number 193953 by Spillover last updated on 24/Jun/23

Name thefollowing Complex compound  (a)[Zn(en)_2 (c_2 o_2 )Br_2 F]^(−5)   (b)Ni(CN)_2 (OH)_3 Cl]  [Fe(H_2 O)_3 (OH)_2 F_2 Br]  (c)[Cr(CN)_4 NO_2 (H_2 O)_2 (NH_3 )_2  ]^(2−)

$${Name}\:{thefollowing}\:{Complex}\:{compound} \\ $$$$\left({a}\right)\left[{Zn}\left({en}\right)_{\mathrm{2}} \left({c}_{\mathrm{2}} {o}_{\mathrm{2}} \right){Br}_{\mathrm{2}} {F}\right]^{−\mathrm{5}} \\ $$$$\left.\left({b}\right){Ni}\left({CN}\right)_{\mathrm{2}} \left({OH}\right)_{\mathrm{3}} {Cl}\right]\:\:\left[{Fe}\left({H}_{\mathrm{2}} {O}\right)_{\mathrm{3}} \left({OH}\right)_{\mathrm{2}} {F}_{\mathrm{2}} {Br}\right] \\ $$$$\left({c}\right)\left[{Cr}\left({CN}\right)_{\mathrm{4}} {NO}_{\mathrm{2}} \left({H}_{\mathrm{2}} {O}\right)_{\mathrm{2}} \left({NH}_{\mathrm{3}} \right)_{\mathrm{2}} \:\right]^{\mathrm{2}−} \\ $$

Answered by Spillover last updated on 25/Jun/23

(a)[Zn(en)_2 (c_2 o_2 )Br_2 F]^(−5)   Dibromo fluoro dioxalato ethly diammine zincate(ii)

$$\left({a}\right)\left[{Zn}\left({en}\right)_{\mathrm{2}} \left({c}_{\mathrm{2}} {o}_{\mathrm{2}} \right){Br}_{\mathrm{2}} {F}\right]^{−\mathrm{5}} \\ $$$${Dibromo}\:{fluoro}\:{dioxalato}\:{ethly}\:{diammine}\:{zincate}\left({ii}\right) \\ $$

Answered by Spillover last updated on 25/Jun/23

(b)Ni(CN)_2 (OH)_3 Cl]  [Fe(H_2 O)_3 (OH)_2 F_2 Br]  Chloro dicyano trihyroxo nickel(viii) bromo  difluoro dihydroxo triaqua ferrate(iii) ion

$$\left.\left({b}\right){Ni}\left({CN}\right)_{\mathrm{2}} \left({OH}\right)_{\mathrm{3}} {Cl}\right]\:\:\left[{Fe}\left({H}_{\mathrm{2}} {O}\right)_{\mathrm{3}} \left({OH}\right)_{\mathrm{2}} {F}_{\mathrm{2}} {Br}\right] \\ $$$${Chloro}\:{dicyano}\:{trihyroxo}\:{nickel}\left({viii}\right)\:{bromo} \\ $$$${difluoro}\:{dihydroxo}\:{triaqua}\:{ferrate}\left({iii}\right)\:{ion} \\ $$$$ \\ $$

Answered by Spillover last updated on 25/Jun/23

(c)[Cr(CN)_4 NO_2 (H_2 O)_2 (NH_3 )_2  ]^(2−)   Tetra cyano nitrito diammine diaqua   crominate(iii)ion

$$\left({c}\right)\left[{Cr}\left({CN}\right)_{\mathrm{4}} {NO}_{\mathrm{2}} \left({H}_{\mathrm{2}} {O}\right)_{\mathrm{2}} \left({NH}_{\mathrm{3}} \right)_{\mathrm{2}} \:\right]^{\mathrm{2}−} \\ $$$${Tetra}\:{cyano}\:{nitrito}\:{diammine}\:{diaqua}\: \\ $$$${crominate}\left({iii}\right){ion} \\ $$

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