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Question Number 198065 by giovi last updated on 09/Oct/23
$$\mathrm{2}^{{x}} +\mathrm{9}+\mathrm{2}^{{x}} =\mathrm{40} \\ $$
Answered by a.lgnaoui last updated on 09/Oct/23
$$\:\mathrm{2}^{\mathrm{x}+\mathrm{1}} =\mathrm{31}\Rightarrow\:\:\left(\:\mathrm{x}+\mathrm{1}\right)\mathrm{ln2}=\mathrm{ln31} \\ $$$$\:\:\mathrm{x}=\frac{\mathrm{ln31}}{\mathrm{ln2}}−\mathrm{1}\:\:\:\:\:\:\:\:\:\boldsymbol{\mathrm{x}}=\frac{\boldsymbol{\mathrm{ln}}\mathrm{31}−\boldsymbol{\mathrm{ln}}\mathrm{2}}{\boldsymbol{\mathrm{ln}}\mathrm{2}} \\ $$