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Question Number 200720 by cortano12 last updated on 22/Nov/23

Answered by BaliramKumar last updated on 22/Nov/23

18+3+8 = 29

$$\mathrm{18}+\mathrm{3}+\mathrm{8}\:=\:\mathrm{29} \\ $$

Answered by Rasheed.Sindhi last updated on 22/Nov/23

Mean=((4+7+10+11+N)/5)=((32+N)/5)=Median C1: N,4,7,10,11⇒((32+N)/5)=7 C2: 4,N,7,10,11⇒((32+N)/5)=7 C3: 4,7,N,10,11⇒((32+N)/5)=N C4: 4,7,10,N,11⇒((32+N)/5)=10 C5: 4,7,10,11,N⇒((32+N)/5)=10 Case A:((32+N)/5)=7 32+N=7×5=35 N=3 Case B: ((32+N)/5)=N⇒4N=32⇒N=8 Case C: ((32+N)/5)=10⇒N=18

$$\mathrm{Mean}=\frac{\mathrm{4}+\mathrm{7}+\mathrm{10}+\mathrm{11}+\mathrm{N}}{\mathrm{5}}=\frac{\mathrm{32}+\mathrm{N}}{\mathrm{5}}=\mathrm{Median} \\ $$$$\mathrm{C1}:\:\:\:\mathrm{N},\mathrm{4},\mathrm{7},\mathrm{10},\mathrm{11}\Rightarrow\frac{\mathrm{32}+\mathrm{N}}{\mathrm{5}}=\mathrm{7} \\ $$$$\mathrm{C2}:\:\:\:\mathrm{4},\mathrm{N},\mathrm{7},\mathrm{10},\mathrm{11}\Rightarrow\frac{\mathrm{32}+\mathrm{N}}{\mathrm{5}}=\mathrm{7} \\ $$$$\mathrm{C3}:\:\:\:\mathrm{4},\mathrm{7},\mathrm{N},\mathrm{10},\mathrm{11}\Rightarrow\frac{\mathrm{32}+\mathrm{N}}{\mathrm{5}}=\mathrm{N} \\ $$$$\mathrm{C4}:\:\:\:\mathrm{4},\mathrm{7},\mathrm{10},\mathrm{N},\mathrm{11}\Rightarrow\frac{\mathrm{32}+\mathrm{N}}{\mathrm{5}}=\mathrm{10} \\ $$$$\mathrm{C5}:\:\:\:\mathrm{4},\mathrm{7},\mathrm{10},\mathrm{11},\mathrm{N}\Rightarrow\frac{\mathrm{32}+\mathrm{N}}{\mathrm{5}}=\mathrm{10} \\ $$$${Case}\:{A}:\frac{\mathrm{32}+\mathrm{N}}{\mathrm{5}}=\mathrm{7} \\ $$$$\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\mathrm{32}+\mathrm{N}=\mathrm{7}×\mathrm{5}=\mathrm{35} \\ $$$$\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\mathrm{N}=\mathrm{3} \\ $$$${Case}\:{B}:\:\frac{\mathrm{32}+\mathrm{N}}{\mathrm{5}}=\mathrm{N}\Rightarrow\mathrm{4N}=\mathrm{32}\Rightarrow\mathrm{N}=\mathrm{8} \\ $$$${Case}\:{C}:\:\frac{\mathrm{32}+\mathrm{N}}{\mathrm{5}}=\mathrm{10}\Rightarrow\mathrm{N}=\mathrm{18} \\ $$

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