Question Number 22478 by 123 45 polytechnicien last updated on 19/Oct/17 | ||
$$\begin{cases}{{x}+{y}^{\mathrm{2}} +{z}^{\mathrm{3}} =\mathrm{3}}\\{{y}+{z}^{\mathrm{2}} +{x}^{\mathrm{3}} =\mathrm{3}}\\{{z}+{x}^{\mathrm{2}} +{z}^{\mathrm{3}} =\mathrm{3}}\end{cases} \\ $$$${trouver}\:{les}\:{solutions}\:{positives} \\ $$$$ \\ $$ | ||
Commented by Rasheed.Sindhi last updated on 19/Oct/17 | ||
$${x}={y}={z}=\mathrm{1} \\ $$ | ||