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Question Number 23722 by Tinkutara last updated on 04/Nov/17

A block of mass m is pulled on the  smooth horizontal floor using two  methods I and II. The ratio of  acceleration (a_I /a_(II) ) is

$$\mathrm{A}\:\mathrm{block}\:\mathrm{of}\:\mathrm{mass}\:{m}\:\mathrm{is}\:\mathrm{pulled}\:\mathrm{on}\:\mathrm{the} \\ $$$$\mathrm{smooth}\:\mathrm{horizontal}\:\mathrm{floor}\:\mathrm{using}\:\mathrm{two} \\ $$$$\mathrm{methods}\:\mathrm{I}\:\mathrm{and}\:\mathrm{II}.\:\mathrm{The}\:\mathrm{ratio}\:\mathrm{of} \\ $$$$\mathrm{acceleration}\:\frac{{a}_{{I}} }{{a}_{{II}} }\:\mathrm{is} \\ $$

Commented by Tinkutara last updated on 04/Nov/17

Commented by mrW1 last updated on 04/Nov/17

(a_I /a_(II) )=4

$$\frac{\mathrm{a}_{\mathrm{I}} }{\mathrm{a}_{\mathrm{II}} }=\mathrm{4} \\ $$

Commented by Tinkutara last updated on 04/Nov/17

Thank you very much Sir!

$$\mathrm{Thank}\:\mathrm{you}\:\mathrm{very}\:\mathrm{much}\:\mathrm{Sir}! \\ $$

Commented by ajfour last updated on 04/Nov/17

a_I =((2F)/m) ;  a_(II) =((F/2)/m) .

$${a}_{{I}} =\frac{\mathrm{2}{F}}{{m}}\:;\:\:{a}_{{II}} =\frac{{F}/\mathrm{2}}{{m}}\:. \\ $$

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