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Question Number 25038 by Tinkutara last updated on 02/Dec/17

For a particle of a rotating rigid body,  v = rω. So  (1) ω ∝ (1/r)  (2) ω ∝ v  (3) v ∝ r  (4) ω is independent of r

$$\mathrm{For}\:\mathrm{a}\:\mathrm{particle}\:\mathrm{of}\:\mathrm{a}\:\mathrm{rotating}\:\mathrm{rigid}\:\mathrm{body}, \\ $$$${v}\:=\:{r}\omega.\:\mathrm{So} \\ $$$$\left(\mathrm{1}\right)\:\omega\:\propto\:\left(\mathrm{1}/{r}\right) \\ $$$$\left(\mathrm{2}\right)\:\omega\:\propto\:{v} \\ $$$$\left(\mathrm{3}\right)\:{v}\:\propto\:{r} \\ $$$$\left(\mathrm{4}\right)\:\omega\:\mathrm{is}\:\mathrm{independent}\:\mathrm{of}\:{r} \\ $$

Answered by ajfour last updated on 02/Dec/17

ω is common for all points of  the rotating rigid body, ω is  independent of r.   since    s=rθ        v=rω ,  so   v ∝ r   (as well) .  (3), (4) are correct .

$$\omega\:{is}\:{common}\:{for}\:{all}\:{points}\:{of} \\ $$$${the}\:{rotating}\:{rigid}\:{body},\:\omega\:{is} \\ $$$${independent}\:{of}\:{r}.\: \\ $$$${since}\:\:\:\:{s}={r}\theta \\ $$$$\:\:\:\:\:\:{v}={r}\omega\:,\:\:{so}\:\:\:{v}\:\propto\:{r}\:\:\:\left({as}\:{well}\right)\:. \\ $$$$\left(\mathrm{3}\right),\:\left(\mathrm{4}\right)\:{are}\:{correct}\:. \\ $$

Commented by Tinkutara last updated on 02/Dec/17

But why (2) is wrong?

$$\mathrm{But}\:\mathrm{why}\:\left(\mathrm{2}\right)\:\mathrm{is}\:\mathrm{wrong}? \\ $$

Commented by ajfour last updated on 02/Dec/17

ω is not a consequence of v .

$$\omega\:{is}\:{not}\:{a}\:{consequence}\:{of}\:{v}\:. \\ $$

Commented by Tinkutara last updated on 02/Dec/17

But since v∝ω, so why not ω∝v?

$${But}\:{since}\:{v}\propto\omega,\:{so}\:{why}\:{not}\:\omega\propto{v}? \\ $$

Commented by Tinkutara last updated on 02/Dec/17

But answer in book is only (3) and (4).

$$\mathrm{But}\:\mathrm{answer}\:\mathrm{in}\:\mathrm{book}\:\mathrm{is}\:\mathrm{only}\:\left(\mathrm{3}\right)\:\mathrm{and}\:\left(\mathrm{4}\right). \\ $$

Commented by Tinkutara last updated on 02/Dec/17

I want to know why (2) is wrong.

$$\mathrm{I}\:\mathrm{want}\:\mathrm{to}\:\mathrm{know}\:\mathrm{why}\:\left(\mathrm{2}\right)\:\mathrm{is}\:\mathrm{wrong}. \\ $$

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