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Question Number 28938 by mondodotto@gmail.com last updated on 01/Feb/18

Commented by Cheyboy last updated on 02/Feb/18

let andre′s money be= x  let Bob′s money be=y  x−20=y+20⇒(1)  2(y−22)=x+22⇒(2)  x−y=40  x−2y=−66  y=106  x=40+106  x=146  Andre has 146  Bob has 106

$${let}\:{andre}'{s}\:{money}\:{be}=\:{x} \\ $$$${let}\:{Bob}'{s}\:{money}\:{be}={y} \\ $$$${x}−\mathrm{20}={y}+\mathrm{20}\Rightarrow\left(\mathrm{1}\right) \\ $$$$\mathrm{2}\left({y}−\mathrm{22}\right)={x}+\mathrm{22}\Rightarrow\left(\mathrm{2}\right) \\ $$$${x}−{y}=\mathrm{40} \\ $$$${x}−\mathrm{2}{y}=−\mathrm{66} \\ $$$${y}=\mathrm{106} \\ $$$${x}=\mathrm{40}+\mathrm{106} \\ $$$${x}=\mathrm{146} \\ $$$${Andre}\:{has}\:\mathrm{146} \\ $$$${Bob}\:{has}\:\mathrm{106} \\ $$$$ \\ $$$$ \\ $$

Commented by mondodotto@gmail.com last updated on 02/Feb/18

please recheck

$$\mathrm{please}\:\mathrm{recheck} \\ $$

Commented by Joel578 last updated on 02/Feb/18

I got the same answer

$$\mathrm{I}\:\mathrm{got}\:\mathrm{the}\:\mathrm{same}\:\mathrm{answer} \\ $$

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