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Question Number 29140 by mathshooter last updated on 04/Feb/18

Find no. of rational roots of f(x)=  2x^(98) +3x^(97) +2x^(96) +.....+2x+3=0.

$${Find}\:{no}.\:{of}\:{rational}\:{roots}\:{of}\:{f}\left({x}\right)= \\ $$$$\mathrm{2}{x}^{\mathrm{98}} +\mathrm{3}{x}^{\mathrm{97}} +\mathrm{2}{x}^{\mathrm{96}} +.....+\mathrm{2}{x}+\mathrm{3}=\mathrm{0}. \\ $$

Commented by math solver last updated on 05/Feb/18

hey , its seems like question   is ambiguous .  in starting with 2 x power is even   but at end it is odd !

$${hey}\:,\:{its}\:{seems}\:{like}\:{question}\: \\ $$$${is}\:{ambiguous}\:. \\ $$$${in}\:{starting}\:{with}\:\mathrm{2}\:{x}\:{power}\:{is}\:{even}\: \\ $$$${but}\:{at}\:{end}\:{it}\:{is}\:{odd}\:! \\ $$

Commented by math solver last updated on 05/Feb/18

btw, what is the ans.?

$${btw},\:{what}\:{is}\:{the}\:{ans}.? \\ $$

Commented by mathshooter last updated on 05/Feb/18

−1  and −(3/2).

$$−\mathrm{1}\:\:{and}\:−\frac{\mathrm{3}}{\mathrm{2}}. \\ $$

Commented by mathshooter last updated on 05/Feb/18

someone plz help.

$${someone}\:{plz}\:{help}. \\ $$

Commented by math solver last updated on 07/Feb/18

yes sir.  q. is wrong.

$${yes}\:{sir}. \\ $$$${q}.\:{is}\:{wrong}. \\ $$

Commented by mrW2 last updated on 06/Feb/18

the function f(x) is not clearly defined.

$${the}\:{function}\:{f}\left({x}\right)\:{is}\:{not}\:{clearly}\:{defined}. \\ $$

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