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Question Number 32076 by rahul 19 last updated on 19/Mar/18
Commented by rahul 19 last updated on 20/Mar/18
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Commented by tanmay.chaudhury50@gmail.com last updated on 23/May/18
Answered by tanmay.chaudhury50@gmail.com last updated on 23/May/18
$${wave}\:{velocity}\:\:{calculated}\:{by}\:{z}={e}^{−\left(\mathrm{2}−{x}\right)^{\mathrm{2}} } \: \\ $$$${the}\:{equation}\:{isz}={e}^{−\left(\mathrm{2}{t}−{x}\right)^{\mathrm{2}} } \:{here}\:{t}=\mathrm{1}\:{given} \\ $$$${so}\:{velocity}\:+{ve}\:{direction}\:{and}\:{velocity}\:{is}=\frac{\mathrm{2}}{\mathrm{1}} \\ $$$$\mathrm{2}{m}/{sec} \\ $$$${pls}\:{see}\:{my}\:{attachment}...{theorem}\:{as}\:{comment} \\ $$