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Question Number 32346 by abdo imad last updated on 23/Mar/18

let u_0 =1 and  u_(n+1) = u_n  ((1+2u_n )/(1+3n))  give a equivalent of u_(n )

$${let}\:{u}_{\mathrm{0}} =\mathrm{1}\:{and}\:\:{u}_{{n}+\mathrm{1}} =\:{u}_{{n}} \:\frac{\mathrm{1}+\mathrm{2}{u}_{{n}} }{\mathrm{1}+\mathrm{3}{n}} \\ $$$${give}\:{a}\:{equivalent}\:{of}\:{u}_{{n}\:} \\ $$

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