Question Number 33557 by JohnQuinceyStClair last updated on 19/Apr/18
![This^ is^ a^ formula. working^ out^ the^ area^ between^ two Toroidal^ coils. Both^ with^ a^ magnetic^ spring^ constant. r=radius=1 a=area=2 k^z =(1/((r+a)))−(1/r^2 )=−a(((2∙r+a))/([(r+a)^2 ∙r^2 ])) ratio=? what^ is^ the^ ratio?](Q33557.png)
$${This}^{} {is}^{} {a}^{} {formula}. \\ $$$${working}^{} {out}^{} {the}^{} {area}^{} {between}^{} {two} \\ $$$${Toroidal}^{} {coils}. \\ $$$${Both}^{} {with}^{} {a}^{} {magnetic}^{} {spring}^{} {constant}. \\ $$$$ \\ $$$${r}={radius}=\mathrm{1} \\ $$$$\mathrm{a}={area}=\mathrm{2} \\ $$$$ \\ $$$$\mathrm{k}^{\mathrm{z}} =\frac{\mathrm{1}}{\left(\mathrm{r}+\mathrm{a}\right)}−\frac{\mathrm{1}}{\mathrm{r}^{\mathrm{2}} }=−\mathrm{a}\frac{\left(\mathrm{2}\centerdot\mathrm{r}+\mathrm{a}\right)}{\left[\left(\mathrm{r}+\mathrm{a}\right)^{\mathrm{2}} \centerdot\mathrm{r}^{\mathrm{2}} \right]} \\ $$$${ratio}=? \\ $$$${what}^{} {is}^{} {the}^{} {ratio}? \\ $$