Question and Answers Forum

All Questions      Topic List

Others Questions

Previous in All Question      Next in All Question      

Previous in Others      Next in Others      

Question Number 3886 by 123456 last updated on 23/Dec/15

f:[0,+∞)→R  g:[0,+∞)→R  f(ux)=f(uf(x))  g(ux)=g(u+f(x))  f(x)+g(x)=?

$${f}:\left[\mathrm{0},+\infty\right)\rightarrow\mathbb{R} \\ $$$${g}:\left[\mathrm{0},+\infty\right)\rightarrow\mathbb{R} \\ $$$${f}\left({ux}\right)={f}\left({uf}\left({x}\right)\right) \\ $$$${g}\left({ux}\right)={g}\left({u}+{f}\left({x}\right)\right) \\ $$$${f}\left({x}\right)+{g}\left({x}\right)=? \\ $$

Commented by Yozzii last updated on 24/Dec/15

Let u=1.  ∴ f(x)+g(x)=f(f(x))+g(1+f(x)).  f(x)=f(f(x))  Let f(x)=x⇒f(f(x))=f(x)=x  and f: [0,∞)→R.  ∴g(x)=g(1+x)  Periodic function with period 1.  g(x)=Asin2πx (A∈R) and g: [0,∞)→R.  ⇒g(x+1)=Asin(2π+2πx)=Asin2πx=g(x)  ∴ f(x)+g(x)=x+Asin2πx for example    g(x)=Asin2mπx+Bcos2nπx (n,m∈Z, A,B∈R)  ∵ g(1+x)=Asin(2mπ+2mπx)+Bcos(2nπ+2πnx)  g(1+x)=Asin2mπx+Bcos2nπx=g(x)    f(x)=0 or f(x)=x.

$${Let}\:{u}=\mathrm{1}. \\ $$$$\therefore\:{f}\left({x}\right)+{g}\left({x}\right)={f}\left({f}\left({x}\right)\right)+{g}\left(\mathrm{1}+{f}\left({x}\right)\right). \\ $$$${f}\left({x}\right)={f}\left({f}\left({x}\right)\right) \\ $$$${Let}\:{f}\left({x}\right)={x}\Rightarrow{f}\left({f}\left({x}\right)\right)={f}\left({x}\right)={x} \\ $$$${and}\:{f}:\:\left[\mathrm{0},\infty\right)\rightarrow\mathbb{R}. \\ $$$$\therefore{g}\left({x}\right)={g}\left(\mathrm{1}+{x}\right) \\ $$$${Periodic}\:{function}\:{with}\:{period}\:\mathrm{1}. \\ $$$${g}\left({x}\right)={Asin}\mathrm{2}\pi{x}\:\left({A}\in\mathbb{R}\right)\:{and}\:{g}:\:\left[\mathrm{0},\infty\right)\rightarrow\mathbb{R}. \\ $$$$\Rightarrow{g}\left({x}+\mathrm{1}\right)={Asin}\left(\mathrm{2}\pi+\mathrm{2}\pi{x}\right)={Asin}\mathrm{2}\pi{x}={g}\left({x}\right) \\ $$$$\therefore\:{f}\left({x}\right)+{g}\left({x}\right)={x}+{Asin}\mathrm{2}\pi{x}\:{for}\:{example} \\ $$$$ \\ $$$${g}\left({x}\right)={Asin}\mathrm{2}{m}\pi{x}+{Bcos}\mathrm{2}{n}\pi{x}\:\left({n},{m}\in\mathbb{Z},\:{A},{B}\in\mathbb{R}\right) \\ $$$$\because\:{g}\left(\mathrm{1}+{x}\right)={Asin}\left(\mathrm{2}{m}\pi+\mathrm{2}{m}\pi{x}\right)+{Bcos}\left(\mathrm{2}{n}\pi+\mathrm{2}\pi{nx}\right) \\ $$$${g}\left(\mathrm{1}+{x}\right)={Asin}\mathrm{2}{m}\pi{x}+{Bcos}\mathrm{2}{n}\pi{x}={g}\left({x}\right) \\ $$$$ \\ $$$${f}\left({x}\right)=\mathrm{0}\:{or}\:{f}\left({x}\right)={x}. \\ $$$$ \\ $$

Terms of Service

Privacy Policy

Contact: info@tinkutara.com