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Question Number 40715 by gopikrishnan005@gmail.com last updated on 26/Jul/18

for x≥2 ∣x−2∣=

$$\mathrm{for}\:\mathrm{x}\geqslant\mathrm{2}\:\mid\mathrm{x}−\mathrm{2}\mid= \\ $$

Commented by maxmathsup by imad last updated on 26/Jul/18

x≥2⇒x−2≥0 ⇒∣x−2∣ =x−2 .

$${x}\geqslant\mathrm{2}\Rightarrow{x}−\mathrm{2}\geqslant\mathrm{0}\:\Rightarrow\mid{x}−\mathrm{2}\mid\:={x}−\mathrm{2}\:. \\ $$

Answered by tanmay.chaudhury50@gmail.com last updated on 26/Jul/18

f(x)=∣x−2∣             =(x−2)  when x>0               =−(x−2)  when x<0                 =0        when  x=0

$${f}\left({x}\right)=\mid{x}−\mathrm{2}\mid \\ $$$$\:\:\:\:\:\:\:\:\:\:\:=\left({x}−\mathrm{2}\right)\:\:{when}\:{x}>\mathrm{0} \\ $$$$\:\:\:\:\:\:\:\:\:\:\:\:\:=−\left({x}−\mathrm{2}\right)\:\:{when}\:{x}<\mathrm{0} \\ $$$$\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:=\mathrm{0}\:\:\:\:\:\:\:\:{when}\:\:{x}=\mathrm{0} \\ $$

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