Question Number 46025 by Sanjarbek last updated on 20/Oct/18
Answered by tanmay.chaudhury50@gmail.com last updated on 20/Oct/18
$${ln}_{{sinx}} {cosx}=\mathrm{4}−{x} \\ $$$$\left({sinx}\right)^{\mathrm{4}−{x}} ={cosx} \\ $$
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Question Number 46025 by Sanjarbek last updated on 20/Oct/18 | ||
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Answered by tanmay.chaudhury50@gmail.com last updated on 20/Oct/18 | ||
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$${ln}_{{sinx}} {cosx}=\mathrm{4}−{x} \\ $$$$\left({sinx}\right)^{\mathrm{4}−{x}} ={cosx} \\ $$ | ||