Question Number 46283 by somil last updated on 23/Oct/18
Answered by tanmay.chaudhury50@gmail.com last updated on 23/Oct/18
$${PQ}=\mathrm{12}\:\:{QR}=\mathrm{5}\:\:{PR}=\sqrt{\mathrm{12}^{\mathrm{2}} +\mathrm{5}^{\mathrm{2}} }\:=\mathrm{13} \\ $$$$ \\ $$$$ \\ $$$$\angle{DQP}=\theta\:\:\angle{DQR}=\mathrm{90}−\theta \\ $$$$\angle{DRQ}=\theta\:\:\:\angle{QPD}=\mathrm{90}−\theta \\ $$$${cot}\angle{DQP} \\ $$$$={cot}\theta \\ $$$$=\frac{\mathrm{5}}{\mathrm{12}} \\ $$$${cos}\angle{DQR} \\ $$$${cos}\left(\mathrm{90}−\theta\right) \\ $$$$=\frac{\mathrm{12}}{\mathrm{13}}\:\:\:{pls}\:{check}... \\ $$