Previous in Relation and Functions Next in Relation and Functions | ||
Question Number 6186 by sanusihammed last updated on 17/Jun/16 | ||
$${If}\:{f}\left({x}\right)\:=\:\mathrm{2}{x}\:\:{and}\:\:{ff}\left({x}\right)\:=\:{x}\:+\:\mathrm{1}\: \\ $$$${then}\:{x}\:=\:? \\ $$ | ||
Commented by Rasheed Soomro last updated on 17/Jun/16 | ||
$${If}\:{f}\left({x}\right)\:=\:\mathrm{2}{x}\:\:{and}\:\:{ff}\left({x}\right)\:=\:{x}\:+\:\mathrm{1}\: \\ $$$${then}\:{x}\:=\:? \\ $$$$−−−−−−−−− \\ $$$${f}\left({x}\right)=\mathrm{2}{x}\Rightarrow{f}\left(\:{f}\left({x}\right)\:\right)={f}\left(\mathrm{2}{x}\right)=\mathrm{2}\left(\mathrm{2}{x}\right)=\mathrm{4}{x}....\left({i}\right) \\ $$$${But}\:\:\:{f}\left(\:{f}\left({x}\right)\:\right)={x}+\mathrm{1}....\left({ii}\right) \\ $$$${From}\:\left({i}\right)\:\&\:\left({ii}\right) \\ $$$$\:\:\:\:\:\:\:\:\:\:\:\mathrm{4}{x}={x}+\mathrm{1} \\ $$$$\:\:\:\:\:\:\:\:\:\:{x}=\frac{\mathrm{1}}{\mathrm{3}} \\ $$ | ||
Commented by sanusihammed last updated on 17/Jun/16 | ||
$${Thank}\:{you}\:{so}\:{much} \\ $$ | ||