Question and Answers Forum

All Questions      Topic List

None Questions

Previous in All Question      Next in All Question      

Previous in None      Next in None      

Question Number 74456 by liki last updated on 24/Nov/19

Commented by liki last updated on 24/Nov/19

...plz anyone knowing simple logic of find the possible number,because this always i did not understand so pl i need simple way of find the others no.

$$...{plz}\:{anyone}\:{knowing}\:{simple}\:{logic}\:{of} \\ $$$${find}\:{the}\:{possible}\:{number},{because}\: \\ $$$$\:{this}\:{always}\:{i}\:{did}\:{not}\:{understand}\:{so}\:{pl}\: \\ $$$$\:{i}\:{need}\:{simple}\:{way}\:{of}\:{find}\:{the}\:{others}\:{no}. \\ $$

Commented by $@ty@m123 last updated on 24/Nov/19

there is no hard and fast rule. Logic & method of solving problem may vary from question to question. You can learn this only through practice.

$${there}\:{is}\:{no}\:{hard}\:{and}\:{fast}\:{rule}. \\ $$$${Logic}\:\&\:{method}\:{of}\:{solving}\:{problem} \\ $$$${may}\:{vary}\:{from}\:{question}\:{to}\:{question}. \\ $$$${You}\:{can}\:{learn}\:{this}\:{only}\: \\ $$$${through}\:{practice}. \\ $$

Answered by mr W last updated on 24/Nov/19

6=2^1 ×3^1 360=2^3 ×3^2 ×5^1 18=2^1 ×3^2 60=2^2 ×3^1 ×5^1 y=2^3 ×3^(1..2) ×5^(0..1) =24,72,120,360

$$\mathrm{6}=\mathrm{2}^{\mathrm{1}} ×\mathrm{3}^{\mathrm{1}} \\ $$$$\mathrm{360}=\mathrm{2}^{\mathrm{3}} ×\mathrm{3}^{\mathrm{2}} ×\mathrm{5}^{\mathrm{1}} \\ $$$$ \\ $$$$\mathrm{18}=\mathrm{2}^{\mathrm{1}} ×\mathrm{3}^{\mathrm{2}} \\ $$$$\mathrm{60}=\mathrm{2}^{\mathrm{2}} ×\mathrm{3}^{\mathrm{1}} ×\mathrm{5}^{\mathrm{1}} \\ $$$${y}=\mathrm{2}^{\mathrm{3}} ×\mathrm{3}^{\mathrm{1}..\mathrm{2}} ×\mathrm{5}^{\mathrm{0}..\mathrm{1}} =\mathrm{24},\mathrm{72},\mathrm{120},\mathrm{360} \\ $$

Commented by liki last updated on 24/Nov/19

..thanks sir,,can you assist me simple logic of get third no,why did you take 2^3 ??

$$..{thanks}\:{sir},,{can}\:{you}\:{assist}\:{me}\:{simple}\:{logic}\: \\ $$$${of}\:{get}\:{third}\:{no},{why}\:{did}\:{you}\:{take}\:\mathrm{2}^{\mathrm{3}} \:?? \\ $$

Commented by mr W last updated on 24/Nov/19

y=2^3 ×3^(1..2) ×5^(0..1) i.e. y_1 =2^3 ×3^1 ×5^0 =24 y_2 =2^3 ×3^2 ×5^0 =72 y_3 =2^3 ×3^1 ×5^1 =120 y_4 =2^3 ×3^2 ×5^1 =360

$${y}=\mathrm{2}^{\mathrm{3}} ×\mathrm{3}^{\mathrm{1}..\mathrm{2}} ×\mathrm{5}^{\mathrm{0}..\mathrm{1}} \\ $$$${i}.{e}. \\ $$$${y}_{\mathrm{1}} =\mathrm{2}^{\mathrm{3}} ×\mathrm{3}^{\mathrm{1}} ×\mathrm{5}^{\mathrm{0}} =\mathrm{24} \\ $$$${y}_{\mathrm{2}} =\mathrm{2}^{\mathrm{3}} ×\mathrm{3}^{\mathrm{2}} ×\mathrm{5}^{\mathrm{0}} =\mathrm{72} \\ $$$${y}_{\mathrm{3}} =\mathrm{2}^{\mathrm{3}} ×\mathrm{3}^{\mathrm{1}} ×\mathrm{5}^{\mathrm{1}} =\mathrm{120} \\ $$$${y}_{\mathrm{4}} =\mathrm{2}^{\mathrm{3}} ×\mathrm{3}^{\mathrm{2}} ×\mathrm{5}^{\mathrm{1}} =\mathrm{360} \\ $$

Commented by liki last updated on 24/Nov/19

...plz mr w,tell me the logic of take 2^3 ..

$$...{plz}\:{mr}\:{w},{tell}\:{me}\:{the}\:{logic}\:{of}\:{take}\:\mathrm{2}^{\mathrm{3}} .. \\ $$

Commented by mr W last updated on 24/Nov/19

in 360 we have 2^3 , but in 18 and 60 we have max. 2^2 , therefore in y we must have at least 2^3 .

$${in}\:\mathrm{360}\:{we}\:{have}\:\mathrm{2}^{\mathrm{3}} ,\:{but}\:{in}\:\mathrm{18}\:{and}\:\mathrm{60}\:{we} \\ $$$${have}\:{max}.\:\mathrm{2}^{\mathrm{2}} ,\:{therefore}\:{in}\:{y}\:{we}\:{must} \\ $$$${have}\:{at}\:{least}\:\mathrm{2}^{\mathrm{3}} . \\ $$

Commented by liki last updated on 24/Nov/19

..Thank you so much sir be blesed

$$..{Thank}\:{you}\:{so}\:{much}\:{sir}\:{be}\:{blesed} \\ $$

Commented by liki last updated on 24/Nov/19

..so it mean to get; y_1 =2^3 ×3^1 =24 y_2 =2^3 ×3^2 =72 y_3 =? y_4 =? ..how to get y_3 & y_4

$$..{so}\:{it}\:{mean}\:{to}\:{get};\:{y}_{\mathrm{1}} =\mathrm{2}^{\mathrm{3}} ×\mathrm{3}^{\mathrm{1}} =\mathrm{24} \\ $$$$\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:{y}_{\mathrm{2}} =\mathrm{2}^{\mathrm{3}} ×\mathrm{3}^{\mathrm{2}} =\mathrm{72} \\ $$$$\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:{y}_{\mathrm{3}} =? \\ $$$$\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:{y}_{\mathrm{4}} =? \\ $$$$..{how}\:{to}\:{get}\:{y}_{\mathrm{3}} \:\&\:{y}_{\mathrm{4}} \\ $$$$ \\ $$

Terms of Service

Privacy Policy

Contact: info@tinkutara.com