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Question Number 76973 by Maclaurin Stickker last updated on 02/Jan/20

In a ABC triangle the side a=6 and  c^2 −b^2 =66. Calculate the projections  of sides b and c on a.

$${In}\:{a}\:{ABC}\:{triangle}\:{the}\:{side}\:\boldsymbol{{a}}=\mathrm{6}\:{and} \\ $$$$\boldsymbol{{c}}^{\mathrm{2}} −\boldsymbol{{b}}^{\mathrm{2}} =\mathrm{66}.\:{Calculate}\:{the}\:{projections} \\ $$$${of}\:{sides}\:\boldsymbol{{b}}\:{and}\:\boldsymbol{{c}}\:{on}\:\boldsymbol{{a}}. \\ $$

Answered by jagoll last updated on 02/Jan/20

projections of sides b on a = ((17)/2)

$$\mathrm{projections}\:\mathrm{of}\:\mathrm{sides}\:\mathrm{b}\:\mathrm{on}\:\mathrm{a}\:=\:\frac{\mathrm{17}}{\mathrm{2}} \\ $$

Answered by jagoll last updated on 02/Jan/20

projections sides c on a = ((17)/2)−6=(5/2)

$$\mathrm{projections}\:\mathrm{sides}\:\mathrm{c}\:\mathrm{on}\:\mathrm{a}\:=\:\frac{\mathrm{17}}{\mathrm{2}}−\mathrm{6}=\frac{\mathrm{5}}{\mathrm{2}} \\ $$

Commented by Maclaurin Stickker last updated on 02/Jan/20

Show how you got the solution.

$${Show}\:{how}\:{you}\:{got}\:{the}\:{solution}. \\ $$

Commented by jagoll last updated on 02/Jan/20

Commented by jagoll last updated on 02/Jan/20

i′m correct my answer

$$\mathrm{i}'\mathrm{m}\:\mathrm{correct}\:\mathrm{my}\:\mathrm{answer} \\ $$

Commented by Maclaurin Stickker last updated on 02/Jan/20

perfect

$${perfect} \\ $$

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