Question and Answers Forum

All Questions      Topic List

None Questions

Previous in All Question      Next in All Question      

Previous in None      Next in None      

Question Number 78309 by otchereabdullai@gmail.com last updated on 15/Jan/20

Answered by mind is power last updated on 15/Jan/20

∠BAO=∠OBA=90−x  ∠BOA=180−∠ABO−∠OAB=180−(90−x+90−x)=2x

$$\angle\mathrm{BAO}=\angle\mathrm{OBA}=\mathrm{90}−\mathrm{x} \\ $$$$\angle\mathrm{BOA}=\mathrm{180}−\angle\mathrm{ABO}−\angle\mathrm{OAB}=\mathrm{180}−\left(\mathrm{90}−\mathrm{x}+\mathrm{90}−\mathrm{x}\right)=\mathrm{2x} \\ $$$$ \\ $$

Commented by otchereabdullai@gmail.com last updated on 16/Jan/20

thank you sir power

$$\mathrm{thank}\:\mathrm{you}\:\mathrm{sir}\:\mathrm{power} \\ $$

Terms of Service

Privacy Policy

Contact: info@tinkutara.com