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Question Number 79485 by ubaydulla last updated on 25/Jan/20

∫(tan^2 x+tan^4 x)dx

$$\int\left(\mathrm{tan}\:^{\mathrm{2}} {x}+\mathrm{tan}\:^{\mathrm{4}} {x}\right){dx} \\ $$

Answered by jagoll last updated on 25/Jan/20

∫ tan^2 x(1+tan^2 x)dx=  ∫tan^2 x d(tan x)= (1/3)tan^3 x+c

$$\int\:\mathrm{tan}\:^{\mathrm{2}} \mathrm{x}\left(\mathrm{1}+\mathrm{tan}\:^{\mathrm{2}} \mathrm{x}\right)\mathrm{dx}= \\ $$$$\int\mathrm{tan}\:^{\mathrm{2}} \mathrm{x}\:\mathrm{d}\left(\mathrm{tan}\:\mathrm{x}\right)=\:\frac{\mathrm{1}}{\mathrm{3}}\mathrm{tan}\:^{\mathrm{3}} \mathrm{x}+\mathrm{c} \\ $$

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