Question and Answers Forum

All Questions      Topic List

Vector Questions

Previous in All Question      Next in All Question      

Previous in Vector      Next in Vector      

Question Number 81498 by jagoll last updated on 13/Feb/20

what the formula  a^�  × (b^� ×c^� ) ?

$$\mathrm{what}\:\mathrm{the}\:\mathrm{formula} \\ $$$$\bar {\mathrm{a}}\:×\:\left(\bar {\mathrm{b}}×\bar {\mathrm{c}}\right)\:? \\ $$

Answered by TANMAY PANACEA last updated on 13/Feb/20

(a^→ .c^→ )b^→ −(a^→ .b^→ )c^→   Tanmay

$$\left(\overset{\rightarrow} {{a}}.\overset{\rightarrow} {{c}}\right)\overset{\rightarrow} {{b}}−\left(\overset{\rightarrow} {{a}}.\overset{\rightarrow} {{b}}\right)\overset{\rightarrow} {{c}} \\ $$$${Tanmay}\: \\ $$

Commented by jagoll last updated on 13/Feb/20

thank you mister

$$\mathrm{thank}\:\mathrm{you}\:\mathrm{mister} \\ $$

Commented by jagoll last updated on 13/Feb/20

i′m forgot this formula

$$\mathrm{i}'\mathrm{m}\:\mathrm{forgot}\:\mathrm{this}\:\mathrm{formula} \\ $$

Commented by mr W last updated on 13/Feb/20

and (a×b)×c=?

$${and}\:\left(\boldsymbol{{a}}×\boldsymbol{{b}}\right)×\boldsymbol{{c}}=? \\ $$

Commented by TANMAY PANACEA last updated on 13/Feb/20

−c^→ ×(a^→ ×b^→ )  =(−c^→ .b^→ )a^→ −(−c^→ .a^→ )b^→   =−(c^→ .b^→ )a^→ +(c^→ .a^→ )b^→   =(c^→ .a^→ )b^→ −(c^→ .b^→ )a^→   pls check

$$−\overset{\rightarrow} {{c}}×\left(\overset{\rightarrow} {{a}}×\overset{\rightarrow} {{b}}\right) \\ $$$$=\left(−\overset{\rightarrow} {{c}}.\overset{\rightarrow} {{b}}\right)\overset{\rightarrow} {{a}}−\left(−\overset{\rightarrow} {{c}}.\overset{\rightarrow} {{a}}\right)\overset{\rightarrow} {{b}} \\ $$$$=−\left(\overset{\rightarrow} {{c}}.\overset{\rightarrow} {{b}}\right)\overset{\rightarrow} {{a}}+\left(\overset{\rightarrow} {{c}}.\overset{\rightarrow} {{a}}\right)\overset{\rightarrow} {{b}} \\ $$$$=\left(\overset{\rightarrow} {{c}}.\overset{\rightarrow} {{a}}\right)\overset{\rightarrow} {{b}}−\left(\overset{\rightarrow} {{c}}.\overset{\rightarrow} {{b}}\right)\overset{\rightarrow} {{a}} \\ $$$${pls}\:{check} \\ $$

Commented by mr W last updated on 13/Feb/20

��

Commented by TANMAY PANACEA last updated on 13/Feb/20

thank you sir

$${thank}\:{you}\:{sir} \\ $$

Terms of Service

Privacy Policy

Contact: info@tinkutara.com