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Question Number 84085 by M±th+et£s last updated on 09/Mar/20 | ||
$${solve} \\ $$$$\frac{{d}}{{dr}}\left({r}\frac{{d}\theta}{{dr}}\right)=\mathrm{0} \\ $$ | ||
Answered by TANMAY PANACEA last updated on 09/Mar/20 | ||
$$\frac{{d}}{{dr}}\left({r}\frac{{d}\theta}{{dr}}\right)=\mathrm{0}=\frac{{dA}}{{dr}}\:\:{A}={constant} \\ $$$${r}\frac{{d}\theta}{{dr}}={A} \\ $$$${d}\theta={A}\frac{{dr}}{{r}}\rightarrow\:\:\:{so}\:\theta={Alnr}+{B} \\ $$ | ||
Commented by M±th+et£s last updated on 09/Mar/20 | ||
$${thank}\:{you}\:{sir} \\ $$ | ||
Commented by TANMAY PANACEA last updated on 09/Mar/20 | ||
$${most}\:{welcome}\:{sir} \\ $$ | ||