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Question Number 84553 by naka3546 last updated on 14/Mar/20

Find  mininum  value  of  n  such  that  both  n + 3   and  2020n + 1  are  square  numbers .

$${Find}\:\:{mininum}\:\:{value}\:\:{of}\:\:{n}\:\:{such}\:\:{that} \\ $$$${both}\:\:{n}\:+\:\mathrm{3}\:\:\:{and}\:\:\mathrm{2020}{n}\:+\:\mathrm{1}\:\:{are}\:\:{square}\:\:{numbers}\:. \\ $$

Commented by mr W last updated on 14/Mar/20

i got n_(min) =2022  2022+3=2025=45^2  ⇒ok  2020×2022+1=(2021−1)(2021+1)+1=2021^2  ⇒ok

$${i}\:{got}\:{n}_{{min}} =\mathrm{2022} \\ $$$$\mathrm{2022}+\mathrm{3}=\mathrm{2025}=\mathrm{45}^{\mathrm{2}} \:\Rightarrow{ok} \\ $$$$\mathrm{2020}×\mathrm{2022}+\mathrm{1}=\left(\mathrm{2021}−\mathrm{1}\right)\left(\mathrm{2021}+\mathrm{1}\right)+\mathrm{1}=\mathrm{2021}^{\mathrm{2}} \:\Rightarrow{ok} \\ $$

Commented by naka3546 last updated on 14/Mar/20

how  about  n = 726 ?

$${how}\:\:{about}\:\:{n}\:=\:\mathrm{726}\:? \\ $$

Commented by mr W last updated on 14/Mar/20

yes. 726 is the smallest n.

$${yes}.\:\mathrm{726}\:{is}\:{the}\:{smallest}\:{n}. \\ $$

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