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Question Number 84627 by M±th+et£s last updated on 14/Mar/20

1)∣sec(x)∣<2tan(x) on[0,2π]    2)find the cirtical points and the range of  f(x)=∣x−3∣+∣2x+1∣

$$\left.\mathrm{1}\right)\mid{sec}\left({x}\right)\mid<\mathrm{2}{tan}\left({x}\right)\:{on}\left[\mathrm{0},\mathrm{2}\pi\right] \\ $$ $$ \\ $$ $$\left.\mathrm{2}\right){find}\:{the}\:{cirtical}\:{points}\:{and}\:{the}\:{range}\:{of} \\ $$ $${f}\left({x}\right)=\mid{x}−\mathrm{3}\mid+\mid\mathrm{2}{x}+\mathrm{1}\mid \\ $$ $$ \\ $$

Commented byTANMAY PANACEA last updated on 14/Mar/20

what is wuestion no 1

$${what}\:{is}\:{wuestion}\:{no}\:\mathrm{1} \\ $$

Commented byM±th+et£s last updated on 14/Mar/20

solve the inequality

$${solve}\:{the}\:{inequality} \\ $$

Answered by TANMAY PANACEA last updated on 14/Mar/20

2) f(x)=∣x−3∣+∣2x+1∣  critical value of x are 3,−0.5  f(x) =x−3+2x+1             =3x−2     when x>3             =7       when x=3             =−(x−3)−(2x+1)   x<−0.5              =−3x+2              =3.5   when x=−0.5              =−(x−3)+2x+1   when  3>x>−0.5             =x+4  so f(x)∈[3.5,∞)

$$\left.\mathrm{2}\right)\:{f}\left({x}\right)=\mid{x}−\mathrm{3}\mid+\mid\mathrm{2}{x}+\mathrm{1}\mid \\ $$ $${critical}\:{value}\:{of}\:{x}\:{are}\:\mathrm{3},−\mathrm{0}.\mathrm{5} \\ $$ $${f}\left({x}\right)\:={x}−\mathrm{3}+\mathrm{2}{x}+\mathrm{1} \\ $$ $$\:\:\:\:\:\:\:\:\:\:\:=\mathrm{3}{x}−\mathrm{2}\:\:\:\:\:{when}\:{x}>\mathrm{3} \\ $$ $$\:\:\:\:\:\:\:\:\:\:\:=\mathrm{7}\:\:\:\:\:\:\:{when}\:{x}=\mathrm{3} \\ $$ $$\:\:\:\:\:\:\:\:\:\:\:=−\left({x}−\mathrm{3}\right)−\left(\mathrm{2}{x}+\mathrm{1}\right)\:\:\:{x}<−\mathrm{0}.\mathrm{5} \\ $$ $$\:\:\:\:\:\:\:\:\:\:\:\:=−\mathrm{3}{x}+\mathrm{2} \\ $$ $$\:\:\:\:\:\:\:\:\:\:\:\:=\mathrm{3}.\mathrm{5}\:\:\:{when}\:{x}=−\mathrm{0}.\mathrm{5} \\ $$ $$\:\:\:\:\:\:\:\:\:\:\:\:=−\left({x}−\mathrm{3}\right)+\mathrm{2}{x}+\mathrm{1}\:\:\:{when}\:\:\mathrm{3}>{x}>−\mathrm{0}.\mathrm{5} \\ $$ $$\:\:\:\:\:\:\:\:\:\:\:={x}+\mathrm{4} \\ $$ $${so}\:{f}\left({x}\right)\in\left[\mathrm{3}.\mathrm{5},\infty\right) \\ $$ $$ \\ $$ $$ \\ $$

Commented byjagoll last updated on 14/Mar/20

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