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Question Number 87116 by lémùst last updated on 02/Apr/20

(d^2 y/dx^2 )+x^2 y=0

$$\frac{{d}^{\mathrm{2}} {y}}{{dx}^{\mathrm{2}} }+{x}^{\mathrm{2}} {y}=\mathrm{0} \\ $$

Answered by redmiiuser last updated on 03/Apr/20

(y^2 /2)+((x^4 .y)/(12))=0

$$\frac{{y}^{\mathrm{2}} }{\mathrm{2}}+\frac{{x}^{\mathrm{4}} .{y}}{\mathrm{12}}=\mathrm{0} \\ $$

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