Question Number 8859 by lepan last updated on 02/Nov/16 | ||
$${If}\:\frac{{tan}\left(\alpha+\beta−\gamma\right)}{{tan}\left({a}−\beta+\gamma\right)}=\frac{{tan}\gamma}{{tan}\beta}\:{then}\:{show} \\ $$$${that}\:{sin}\left(\beta−\gamma\right)=\mathrm{0}\:{or}\:{sin}\mathrm{2}\alpha+{sin}\mathrm{2}\beta+{sin}\mathrm{2}\Upsilon=\mathrm{0}. \\ $$ | ||
Answered by myintkhaing last updated on 03/Nov/16 | ||
Commented by myintkhaing last updated on 03/Nov/16 | ||
$${credit}\:{Kyaw}\:{Zay}\:{Myint} \\ $$ | ||