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Question Number 90503 by john santu last updated on 24/Apr/20
Commented by john santu last updated on 24/Apr/20
$${a}\:{total}\:{of}\:\mathrm{20}\:{marble}\: \\ $$
Commented by jagoll last updated on 24/Apr/20
$${probability}\:{sue}\:{will}\:{win}\:{a}\:{game}\: \\ $$$$=\:\frac{\mathrm{5}}{\mathrm{6}}×\frac{\mathrm{6}}{\mathrm{20}}\:=\:\frac{\mathrm{1}}{\mathrm{4}}\:=\:\mathrm{25\%} \\ $$