Question Number 90801 by john santu last updated on 26/Apr/20
$${what}\:{are}\:{the}\:{next}\:{two}\:{number}\: \\ $$$${of}\:{this}\:{series}\:\mathrm{4},\mathrm{7},\mathrm{9},\mathrm{2},\mathrm{5},\mathrm{6},\mathrm{3},\mathrm{8}\:? \\ $$
Commented by MJS last updated on 26/Apr/20
$${a}_{{n}} =−\frac{\mathrm{17}}{\mathrm{630}}{n}^{\mathrm{7}} +\frac{\mathrm{643}}{\mathrm{720}}{n}^{\mathrm{6}} −\frac{\mathrm{8683}}{\mathrm{720}}{n}^{\mathrm{5}} +\frac{\mathrm{12287}}{\mathrm{144}}{n}^{\mathrm{4}} −\frac{\mathrm{242917}}{\mathrm{720}}{n}^{\mathrm{3}} +\frac{\mathrm{263981}}{\mathrm{360}}{n}^{\mathrm{2}} −\frac{\mathrm{27791}}{\mathrm{35}}{n}+\mathrm{328} \\ $$$${a}_{\mathrm{9}} =−\mathrm{122} \\ $$$${a}_{\mathrm{10}} =−\mathrm{1163} \\ $$
Commented by john santu last updated on 26/Apr/20
$${waw}.... \\ $$
Commented by MJS last updated on 27/Apr/20
$$\mathrm{you}\:\mathrm{know}\:\mathrm{this}\:\mathrm{is}\:\mathrm{only}\:\mathrm{one}\:\mathrm{possibility}...\:\mathrm{the} \\ $$$$\mathrm{next}\:\mathrm{two}\:\mathrm{numbers}\:\mathrm{can}\:\mathrm{be}\:\mathrm{any}\:{z}_{\mathrm{1}} ,\:{z}_{\mathrm{2}} \:\in\mathbb{C} \\ $$