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Question Number 91291 by jagoll last updated on 29/Apr/20
$${x}\:{dy}\:+\mathrm{2}{y}\:{dx}\:=\:\mathrm{2}{x}^{\mathrm{3}} {y}^{\mathrm{2}} \:{dx} \\ $$
Commented by john santu last updated on 29/Apr/20
$${Bernoulli}\:{diff}\:{eq}\: \\ $$
Commented by john santu last updated on 29/Apr/20
Commented by jagoll last updated on 29/Apr/20
$${thx}\:{sir} \\ $$