Question Number 97114 by fortunat last updated on 06/Jun/20
$${pls}\:{find}\:{x} \\ $$$$ \\ $$$${x}^{{x}^{{x}} } +{ln}\left(\mathrm{2}{x}\right)−\mathrm{1}=\mathrm{0} \\ $$
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Question Number 97114 by fortunat last updated on 06/Jun/20 | ||
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$${pls}\:{find}\:{x} \\ $$$$ \\ $$$${x}^{{x}^{{x}} } +{ln}\left(\mathrm{2}{x}\right)−\mathrm{1}=\mathrm{0} \\ $$ | ||