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Atomic StructureQuestion and Answers: Page 1

Question Number 203877    Answers: 0   Comments: 0

$$\mathrm{Write}\:\mathrm{a}\:\mathrm{balanced}\:\mathrm{Ionic}\:\mathrm{chemical}\:\mathrm{equation} \\ $$$$\:\mathrm{for}\:\mathrm{the}\:\mathrm{following}\:\mathrm{reaction} \\ $$$$\left(\mathrm{a}\right){HCl}+{C}\mathrm{aCO}_{\mathrm{3}} \rightarrow\mathrm{Ca}{Cl}_{\mathrm{2}} +{C}\mathrm{O}_{\mathrm{2}\left(\mathrm{g}\right)} +\mathrm{H}_{\mathrm{2}} \mathrm{O}_{\left({l}\right)} \\ $$$$\left({b}\right){NH}_{\mathrm{4}} {OH}_{\:\left({aq}\right)} +{HCl}_{\left({aq}\right)} \:\rightarrow{NH}_{\mathrm{4}} \mathrm{C}{l}_{\left({aq}\right)} +{H}_{\mathrm{2}} \mathrm{O}_{\left({l}\right)} \\ $$$$\mathrm{31}/\mathrm{1}/\mathrm{2024} \\ $$

Question Number 193437    Answers: 0   Comments: 0

$$\mathrm{in}\:\mathrm{the}\:\mathrm{malicol}\:\mathrm{of}\:\mathrm{CaCO}_{\mathrm{3}} \:\mathrm{how}\:\mathrm{many} \\ $$$$\sigma\:\mathrm{and}\:\pi\:\mathrm{bond}\:\mathrm{has}? \\ $$

Question Number 188808    Answers: 0   Comments: 2

$${how}\:{is}\:{solution} \\ $$$$\mathrm{72}.\mathrm{5}{gr}\:\:\:{of}\:{the}\:\left[{C}_{\mathrm{3}} {H}_{\mathrm{6}} {O}\right]\:{how}\:{many}\:\mathrm{Molecule}\:{of}\:\left[{H}\right]\:{exist}? \\ $$

Question Number 188775    Answers: 1   Comments: 0

$${how}\:{is}\:{solution} \\ $$$$\mathrm{72}.\mathrm{5}{gr}\:\:\:{of}\:{the}\:\left[{C}_{\mathrm{3}} {H}_{\mathrm{6}} {O}\right]\:{how}\:{many}\:\mathrm{Molecule}\:{of}\:\left[{H}\right]\:{exist}? \\ $$

Question Number 178019    Answers: 0   Comments: 0

$$\mathrm{Give}\:\mathrm{the}\:\mathrm{IUPAC}\:\mathrm{name}\:\mathrm{of}\:\mathrm{the} \\ $$$$\mathrm{following} \\ $$$$\left(\mathrm{a}\right)\mathrm{H}_{\mathrm{3}} \mathrm{PO}_{\mathrm{4}} \\ $$$$\left(\mathrm{b}\right)\mathrm{H}_{\mathrm{2}} \mathrm{CO}_{\mathrm{3}} \\ $$$$\left(\mathrm{c}\right)\mathrm{HCIO} \\ $$$$\left(\mathrm{d}\right)\:\mathrm{HNO}_{\mathrm{2}} \\ $$$$\left(\mathrm{e}\right)\mathrm{HNO}_{\mathrm{3}} \\ $$$$\left(\mathrm{f}\right)\mathrm{Al}_{\mathrm{2}} \left(\mathrm{SO}_{\mathrm{4}} \right)_{\mathrm{3}} \\ $$$$\left(\mathrm{g}\right)\mathrm{Ca}_{\mathrm{3}} \left(\mathrm{PO}_{\mathrm{4}} \right)_{\mathrm{2}} \\ $$$$\left(\mathrm{h}\right)\mathrm{MgO}_{\mathrm{2}} \\ $$$$\left(\mathrm{i}\right)\mathrm{HF} \\ $$

Question Number 178018    Answers: 2   Comments: 0

$$\mathrm{8}.\mathrm{1g}\:\mathrm{of}\:\mathrm{a}\:\mathrm{compound}\:\mathrm{Q}\:\mathrm{contain} \\ $$$$\mathrm{magnessium}\:\mathrm{and}\:\mathrm{oxygen}.\mathrm{if} \\ $$$$\mathrm{mass}\:\mathrm{of}\:\mathrm{magnessium}\:\mathrm{is}\:\mathrm{4}.\mathrm{9g} \\ $$$$\mathrm{Determine}\:\mathrm{the}\:\mathrm{empirical}\:\mathrm{formular} \\ $$$$\mathrm{of}\:\mathrm{compound}\:\mathrm{Q}. \\ $$$$\left[\mathrm{given}\:\mathrm{Mg}=\mathrm{24}\:\:\:\mathrm{O}=\mathrm{16}\right] \\ $$

Question Number 178013    Answers: 4   Comments: 0

$$\mathrm{Using}\:\mathrm{Electronic}\:\mathrm{diagrams}\:\mathrm{show} \\ $$$$\mathrm{the}\:\mathrm{bonding}\:\mathrm{in}\:\mathrm{the}\:\mathrm{following} \\ $$$$\left(\mathrm{a}\right)\mathrm{Magnesium}\:\mathrm{chloride} \\ $$$$\left(\mathrm{b}\right)\mathrm{Sodium}\:\mathrm{chloride} \\ $$

Question Number 178011    Answers: 3   Comments: 0

$$\mathrm{Hydrocarbon}\:\mathrm{contain}\:\mathrm{80\%}\:\mathrm{by} \\ $$$$\mathrm{mass}\:\mathrm{of}\:\mathrm{carbon}\:\mathrm{and}\:\mathrm{the}\:\mathrm{rest} \\ $$$$\mathrm{is}\:\mathrm{for}\:\mathrm{hydrogen}.\mathrm{calculate}\:\mathrm{the} \\ $$$$\mathrm{empirical}\:\mathrm{formula}\:\mathrm{of}\:\mathrm{the}\:\mathrm{compound} \\ $$$$\left[\mathrm{given}\:\mathrm{H}=\mathrm{1}\:\:\mathrm{C}=\mathrm{12}\right] \\ $$

Question Number 178009    Answers: 3   Comments: 2

Question Number 177606    Answers: 2   Comments: 0

Question Number 177605    Answers: 2   Comments: 0

Question Number 166678    Answers: 1   Comments: 0

$$\mathrm{4}+\boldsymbol{{x}}+\mathrm{2}\boldsymbol{{x}}=\mathrm{8}+\mathrm{2}\left(\mathrm{3}+\boldsymbol{{x}}\right)−\mathrm{3} \\ $$$$\boldsymbol{{F}}{ind}\:{x} \\ $$$$ \\ $$

Question Number 159786    Answers: 0   Comments: 0

$$\mathrm{Work}\:\mathrm{out}\:\mathrm{and}\:\mathrm{sketch}\:\mathrm{P}_{\mathrm{y}} \:\mathrm{orbitals} \\ $$

Question Number 159785    Answers: 0   Comments: 0

$$\mathrm{work}\:\mathrm{out}\:\mathrm{and}\:\mathrm{sketch}\:\mathrm{d}−\mathrm{orbital}\:\mathrm{for}\:\mathrm{the}\:\mathrm{function} \\ $$$$\left.\mathrm{i}\right)\:\mathrm{f}_{\mathrm{1}} =\mathrm{3Cos}^{\mathrm{2}} \theta−\mathrm{1} \\ $$$$\left.\mathrm{i}\right)\:\mathrm{f}_{\mathrm{2}} =\mathrm{Sin}\theta\mathrm{Cos}\theta\mathrm{Cos}\phi \\ $$

Question Number 135326    Answers: 0   Comments: 0

Question Number 125015    Answers: 2   Comments: 0

Question Number 121091    Answers: 0   Comments: 1

Question Number 90327    Answers: 0   Comments: 1

Question Number 77890    Answers: 0   Comments: 0

Question Number 75860    Answers: 1   Comments: 0

$${complete}\:{and}\:{balance}\: \\ $$$${S}+{HNO}_{\mathrm{3}} \rightarrow \\ $$$$ \\ $$

Question Number 64101    Answers: 0   Comments: 1

$${why}\:{the}\:{first}\:{ionisation}\left(\bigtriangleup{H}_{{i}\mathrm{1}} \right){energy}\:{of}\:{Oxygen}\:{smaller} \\ $$$${than}\:{the}\:{second}? \\ $$$${A}.\:{Due}\:{to}\:{the}\:{nuclear}\:{charge} \\ $$$${B}.\:{Due}\:{to}\:{the}\:{distance}\:{of}\:{the}\:{electron}\:{from}\:{the}\:{nucleus} \\ $$$${C}.\:{Due}\:{to}\:{the}\:{effect}\:{of}\:{spin}−{pair}\:{repulsion} \\ $$$${D}.\:{Due}\:{to}\:{a}\:{shielding}\:{effect}. \\ $$

Question Number 53086    Answers: 0   Comments: 1

$$\mathrm{JEE}\:\mathrm{Main}\:\mathrm{chemistry}\:\mathrm{errors}\:\mathrm{by} \\ $$$$\mathrm{Resonance}.\:\mathrm{Today}\:\mathrm{is}\:\mathrm{the}\:\mathrm{last}\:\mathrm{day} \\ $$$$\mathrm{for}\:\mathrm{raising}\:\mathrm{objectiions}. \\ $$$$\mathrm{You}\:\mathrm{need}\:\mathrm{to}\:\mathrm{tap}\:\mathrm{once}\:\mathrm{to}\:\mathrm{select}\:\mathrm{and}\:\mathrm{tap} \\ $$$$\mathrm{the}\:\mathrm{text}\:\mathrm{again}\:\mathrm{to}\:\mathrm{open}\:\mathrm{hyperlink}. \\ $$

Question Number 52991    Answers: 1   Comments: 1

Question Number 50451    Answers: 2   Comments: 0

$${how}\:{can}\:{i}\:{derive}\:{a}\:{formula}\:{to}\:{calculate}\:{the}\:{speed}\:{of}\:{an}\:{electron} \\ $$$${in}\:{n}^{{th}} \:{orbit}\:{of}\:{a}\:{hydrogen}\:{atom}? \\ $$

Question Number 32471    Answers: 0   Comments: 0

Question Number 32423    Answers: 0   Comments: 0

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