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Question Number 200125 Answers: 0 Comments: 0
$$\mathrm{NO}_{\mathrm{2}} \left(\mathrm{g}\right)\:\Rightarrow\:\mathrm{2NO}\:\left(\mathrm{g}\right)+\mathrm{O}_{\mathrm{2}} \:\left(\mathrm{g}\right)\:\mathrm{at}\:\mathrm{300}°\mathrm{C} \\ $$$$\mathrm{The}\:\mathrm{initial}\:\mathrm{concentration}\:\mathrm{of}\:\mathrm{NO}_{\mathrm{2}} \:\mathrm{is}\: \\ $$$$\mathrm{0}.\mathrm{01}\:\mathrm{mol}/\mathrm{L}\:\mathrm{and}\:\mathrm{its}\:\mathrm{concentration}\: \\ $$$$\mathrm{after}\:\mathrm{150}\:\mathrm{s}\:\mathrm{is}\:.\mathrm{0055}\:\mathrm{mol}/\mathrm{L}.\:\mathrm{What}\:\mathrm{are} \\ $$$$\:\mathrm{the}\:\mathrm{average}\:\mathrm{rates}\:\mathrm{of}\:\mathrm{the}\:\mathrm{above} \\ $$$$\:\mathrm{reaction}\:\mathrm{during}\:\mathrm{the}\:\mathrm{first}\:\mathrm{150}\:\mathrm{s}\:\mathrm{and} \\ $$$$\:\mathrm{during}\:\mathrm{the}\:\mathrm{second}\:\mathrm{150}\:\mathrm{s}? \\ $$
Question Number 200104 Answers: 0 Comments: 0
Question Number 73347 Answers: 0 Comments: 0
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