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Coordinate GeometryQuestion and Answers: Page 1

Question Number 206643    Answers: 2   Comments: 0

Question Number 205631    Answers: 1   Comments: 0

Question Number 205517    Answers: 1   Comments: 0

Question Number 205479    Answers: 1   Comments: 0

Question Number 205372    Answers: 0   Comments: 0

Question Number 204168    Answers: 1   Comments: 1

Question Number 204145    Answers: 1   Comments: 0

Question Number 204062    Answers: 4   Comments: 0

I. A(−5, −1); B(3, −5); C(5, 2) ar(△ABC) = ? II. A(5, 3); B(2, 5); C(−5, 3); D(−4, −3) ar(□ABCD) = ? shortest solution

$$\mathrm{I}.\:\:\:\:\:\:\:\mathrm{A}\left(−\mathrm{5},\:−\mathrm{1}\right);\:\mathrm{B}\left(\mathrm{3},\:−\mathrm{5}\right);\:\mathrm{C}\left(\mathrm{5},\:\mathrm{2}\right)\:\:\:\:\:\:{ar}\left(\bigtriangleup\mathrm{ABC}\right)\:=\:? \\ $$$$\mathrm{II}.\:\:\:\:\:\mathrm{A}\left(\mathrm{5},\:\mathrm{3}\right);\:\mathrm{B}\left(\mathrm{2},\:\mathrm{5}\right);\:\mathrm{C}\left(−\mathrm{5},\:\mathrm{3}\right);\:\mathrm{D}\left(−\mathrm{4},\:−\mathrm{3}\right)\:\:\:\:\:\:\:{ar}\left(\Box\mathrm{ABCD}\right)\:=\:? \\ $$$$\mathrm{shortest}\:\mathrm{solution}\: \\ $$

Question Number 203465    Answers: 2   Comments: 0

Focus and vertex of a parabola are at (3, 4) and (0,0). Find the equation of the directrix.

$$\mathrm{Focus}\:\mathrm{and}\:\mathrm{vertex}\:\mathrm{of}\:\mathrm{a}\:\mathrm{parabola}\:\mathrm{are}\:\mathrm{at}\:\left(\mathrm{3},\:\mathrm{4}\right)\:\mathrm{and}\:\left(\mathrm{0},\mathrm{0}\right). \\ $$$$\mathrm{Find}\:\mathrm{the}\:\mathrm{equation}\:\mathrm{of}\:\mathrm{the}\:\mathrm{directrix}. \\ $$

Question Number 203159    Answers: 0   Comments: 0

Q202938 the value of x is 15 (Voir reponse develope )

$$\mathrm{Q202938} \\ $$$$\mathrm{the}\:\mathrm{value}\:\mathrm{of}\:\boldsymbol{\mathrm{x}}\:\boldsymbol{\mathrm{is}}\:\mathrm{15}\: \\ $$$$\left(\boldsymbol{{Voir}}\:\boldsymbol{{reponse}}\:\boldsymbol{{develope}}\:\right) \\ $$

Question Number 201989    Answers: 1   Comments: 0

Question Number 201829    Answers: 2   Comments: 0

shortest distance from (−6,0)to x^2 −y^2 +16=0

$${shortest}\:{distance}\:{from}\:\left(−\mathrm{6},\mathrm{0}\right){to}\:{x}^{\mathrm{2}} −{y}^{\mathrm{2}} +\mathrm{16}=\mathrm{0} \\ $$

Question Number 201660    Answers: 1   Comments: 0

An equilateral triangle inscribed in a parabola y^2 =4x. One of its vertices is at the vertex of the parabola. Find the length of each side of the triangle in units.

$${An}\:{equilateral}\:{triangle}\:{inscribed}\:{in}\:{a}\:{parabola} \\ $$$${y}^{\mathrm{2}} =\mathrm{4}{x}.\:{One}\:{of}\:{its}\:{vertices}\:{is}\:{at}\:{the}\:{vertex}\:{of}\:\:{the}\:{parabola}. \\ $$$${Find}\:{the}\:{length}\:{of}\:{each}\:{side}\:{of}\:{the}\:{triangle}\:{in}\:{units}. \\ $$

Question Number 201659    Answers: 2   Comments: 0

Find the shortest distance between point A(3,2) and curve y=(√x) (x>0).

$${Find}\:{the}\:{shortest}\:{distance}\:{between}\: \\ $$$${point}\:{A}\left(\mathrm{3},\mathrm{2}\right)\:{and}\:{curve}\:{y}=\sqrt{{x}}\:\left({x}>\mathrm{0}\right). \\ $$

Question Number 201581    Answers: 1   Comments: 0

Question Number 201383    Answers: 0   Comments: 2

Question Number 201323    Answers: 0   Comments: 0

Question Number 200636    Answers: 1   Comments: 5

1−Determiner la valeur de EF 2−Laire du triangle ADE

$$\mathrm{1}−\mathrm{Determiner}\:\mathrm{la}\:\mathrm{valeur}\:\mathrm{de}\:\:\boldsymbol{\mathrm{EF}} \\ $$$$\mathrm{2}−\mathrm{Laire}\:\mathrm{du}\:\mathrm{triangle}\:\:\boldsymbol{\mathrm{ADE}} \\ $$$$ \\ $$

Question Number 200196    Answers: 2   Comments: 3

the minimum of (x+y+z)?

$$\mathrm{the}\:\mathrm{minimum}\:\mathrm{of}\:\left(\mathrm{x}+\mathrm{y}+\mathrm{z}\right)? \\ $$

Question Number 200183    Answers: 0   Comments: 0

Question Number 200085    Answers: 1   Comments: 2

perimetre of White triangle?

$$\mathrm{perimetre}\:\mathrm{of}\:\:\mathrm{White}\:\mathrm{triangle}? \\ $$

Question Number 199940    Answers: 2   Comments: 3

Question Number 199838    Answers: 1   Comments: 0

Question Number 199834    Answers: 1   Comments: 1

Let C be the circle with the center (2,3) and radius 5 a) show that P(5,7) lies on C and find the equation of the tangent at P b) show that the line 3x−4y+31=0 is a tangent to C

$$\boldsymbol{{Let}}\:\boldsymbol{{C}}\:\boldsymbol{{be}}\:\boldsymbol{{the}}\:\boldsymbol{{circle}}\:\boldsymbol{{with}}\:\boldsymbol{{the}}\:\boldsymbol{{center}}\:\left(\mathrm{2},\mathrm{3}\right)\:\boldsymbol{{and}}\:\boldsymbol{{radius}}\:\mathrm{5} \\ $$$$\left.\boldsymbol{{a}}\right)\:\boldsymbol{{show}}\:\boldsymbol{{that}}\:\boldsymbol{{P}}\left(\mathrm{5},\mathrm{7}\right)\:\boldsymbol{{lies}}\:\boldsymbol{{on}}\:\boldsymbol{{C}}\:\boldsymbol{{and}}\:\boldsymbol{{find}}\:\boldsymbol{{the}} \\ $$$$\boldsymbol{{equation}}\:\boldsymbol{{of}}\:\boldsymbol{{the}}\:\boldsymbol{{tangent}}\:\boldsymbol{{at}}\:\boldsymbol{{P}} \\ $$$$\left.\boldsymbol{{b}}\right)\:\boldsymbol{{show}}\:\boldsymbol{{that}}\:\boldsymbol{{the}}\:\boldsymbol{{line}}\:\mathrm{3}\boldsymbol{{x}}−\mathrm{4}\boldsymbol{{y}}+\mathrm{31}=\mathrm{0}\:\boldsymbol{{is}}\:\boldsymbol{{a}}\:\boldsymbol{{tangent}}\:\boldsymbol{{to}}\:\boldsymbol{{C}} \\ $$

Question Number 199825    Answers: 1   Comments: 0

Question Number 199817    Answers: 2   Comments: 0

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