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Question Number 134329 by bramlexs22 last updated on 02/Mar/21
$$ \\ $$How many ways can 15 basketball players be assigned to Team A, Team B, and Team C with 5 players on each team?
Answered by EDWIN88 last updated on 02/Mar/21
$$\:=\frac{\mathrm{15}!}{\left(\mathrm{5}!\right)^{\mathrm{3}} }\:=\:\mathrm{756}\:\mathrm{756} \\ $$
Answered by mr W last updated on 02/Mar/21
$${C}_{\mathrm{5}} ^{\mathrm{15}} ×{C}_{\mathrm{5}} ^{\mathrm{10}} =\mathrm{756756} \\ $$
Commented by otchereabdullai@gmail.com last updated on 12/Mar/21
$$\mathrm{wow}! \\ $$